That's normally correct for the kernel. However, if someone has built the preemptive option into the kernel, two calls in an unlikely, but quick succession could cause the problem you're talking about. -Phil/CERisE On Mon, Jun 21, 2004 at 08:21:31AM -0700, l x wrote: > Hi, > > I'm working on a module and would appreciate it if > some one could help me on this. > > Suppose there are two modules, modA and modB. What's > going to happen if modB calls a function, > modA_func_2(), defined in modA while modA is running > another function of its own, modA_func_1()? > > I need modA completes modA_func_1() before responsing > to modB's call to modA_func_2(). Can I assume kernel > will do this for me? If I understand right, a module > runs as a single thread process. Therefore, when > something is running, other requests must wait. > Please correct me if I'm wrong. > > Thanks, > > > T. > > > > > __________________________________ > Do you Yahoo!? > New and Improved Yahoo! Mail - 100MB free storage! > http://promotions.yahoo.com/new_mail > > -- > Kernelnewbies: Help each other learn about the Linux kernel. > Archive: http://mail.nl.linux.org/kernelnewbies/ > FAQ: http://kernelnewbies.org/faq/ > -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
