On Thu, Jan 22, 2004 at 22:22:01 -0800, prasanna wakhare wrote: > Hi all, > sorry for silly question again. > > in *(int * )0=0 > > we are dereferencing the NULL pointer coz' Sure we do. > (int *)0 is pointer to NULL It's THE NULL pointer. (NULL is not a variable, so there is no pointer TO NULL). > and *(int *)0 is what we called dereferencing the ptr, > > but about syntax > > (int *)0 --> how compiler interprets it while > parsing phase or in any complex pointer assignment > can anybody explain this syntax? Type in parenthesis (eg. (int *)) is a typecast operator. Thus 0 (which is a constant of type int) is cast to (int *). Casting integeral type to pointer means to intepret the integeral value as an address. ------------------------------------------------------------------------------- Jan 'Bulb' Hudec <bulb@ucw.cz> -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
