> 4 struct task_struct;
> 5
> 6 static inline struct task_struct * get_current(void)
> 7 {
> 8 struct task_struct *current;
> 9 __asm__("andl %%esp,%0; ":"=r" (current) : "0" (~8191UL));
> 10 return current;
> 11}
> 12
> 13 #define current get_current()
>
> Look beyond the macro.
just as well say "look in the closet". maybe the boggy man is there??? ;)
but seriously, look at the previous email:
> > > current is globally defined as
> > > a task_struct that point to current user.
so, current is not __globally__ defined, and that is what i meant.
current gets recalculated upon each call to the macro, hence it is not
globally defined. (semantics, semantics... )
cheers.
========================================================================
nir.
--
Kernelnewbies: Help each other learn about the Linux kernel.
Archive: http://mail.nl.linux.org/kernelnewbies/
FAQ: http://kernelnewbies.org/faq/
