Interrupt Descriptor Table question.

["Bryan K." <ef057@hotmail.com>]

I was trying to figure out where in the memory lives the interrupt 
descriptor table. I wrote the following code which is called at start_kernel 
bofore smp_init. My problem is that the printk prints 0xc0330000. This is 
supposed to be physical memory pointer right? (I don't have that much 
memory).  I do not believe this is a kernel virtual memory pointer. What am 
I missing?

void print_idt(void)
{
       unsigned int idt = 0;
       unsigned char itdr[6];

       __asm__ volatile ("sidt %0\t\n" : "=m" (itdr));
       idt = *((unsigned long *) &itdr[2]);
       printk("idt is at %p\n", idt);
}

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