* Vamsi Krishna <krishna_k@students.iiit.net> [2003-05-29 20:21]:
> Hi ,
>
> Iam stuck up with the following problem during modification of a part
> of the kernel code. The problem is to create an "Array of function
> pointers dynamically". I tried to solve the problem in this way.
>
> -----------------------------------------------------------------------
>
> int * function(); /*declaration*/
>
> int *(**array_of_function_pointers)(); /*declaration of function pointer
> array*/
>
> /*The sizeof the array ie (array_of_function_pointers) is not know
> before hand so I need to create dynamically.
>
> If the size of array is known then
> "int *(*array_of_function_pointers[SIZE])()" works
> */
>
> /*Allocating memory for array_of_function_pointers */
>
> array_of_function_pointers = (XXXX) malloc(sizeof(YYYY)*SIZE);
> ------ -----
>
> array_of_function_pointers[1]=function;
>
> (*array_of_function_pointers[1])(); /*function call*/
>
> -----------------------------------------------------------------
>
> what should i keep in the place of XXXX and YYYY in the above code.
>
well, I assume this is rather a basic C programming problem than Linux
Kernel related stuff. Anyway:
typedef int *(*function_t)(void); /* assuming you would want to return
a pointer to an int */
function_t *function_array;
function_array = (function_t *)malloc(sizeof(function_t) * size_of_array);
/* btw, a function pointer is just a void pointer */
Please correct if mistaken.
wbr,
Lukas
--
Lukas Ruf | Wanna know anything about raw |
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