instead of changing the timer interrupt why dont u use timer_bh or immediate_bh bottom halves of timer interrupt. i mean u can register ur code to be executed every timer interrupt if u register to these bottom halves. hth, raghu On Thu, 2 Jan 2003, Geert Fannes wrote: > hello, > > i am working on a drivermodule to control a stepper motor using the > parallel port. i need a timer mechanism with a higher frequency than the > jiffies clock. i tried to register an interrupt handler for IRQ0, but > the code > > request_irq(0,stepper_isr,SA_SHIRQ,"stepper",&iNothing) > > fails and returns -16 (16 == EBUSY, 12 == ENOMEM, 22 == EINVAL, so i > guess that the "-" characters in `man request_irq` in the return value > section are really minus signs, and not some item indicators. i mean: > can i interpret "-16" as being EBUSY?). i tried also using the flags > SA_INTERRUPT|SA_SHIRQ, but it gave the same result, so i gues the timer > interrupt cannot be shared using request_irq(). > > - can anyone tell me what i am doing wrong? > - or how i can get my interrupt service routine called at each IRQ0 (i > played a bit with writing interrupt handler in dos using assembler, but > i don't know if i can do the same things in protected mode. if i > remember correct, the isr for irq0 can be found at addres 0x0000 till > 0x0003, so can i just replace this with my isr and call the original > linux timer isr at the end of my isr)? > - (or where i can find the linux timer interrupt handler in the source > so i can extend this (last option))? > > (i run the latest mandrake and/or the latest debian) > > greetings and happy newyear, > geert. > > -- > Kernelnewbies: Help each other learn about the Linux kernel. > Archive: http://mail.nl.linux.org/kernelnewbies/ > FAQ: http://kernelnewbies.org/faq/ > -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
