I could not understand what you were doing with that if-statement. The
following works for me:
#define k_message(msg...) printk(KERN_INFO msg)
if you want to make it conditional w.r.t. MYDEBUG it would look like
#ifdef MYDEBUG
#define ...
#else
#define ...
#endif
On Mon, 25 Feb 2002, Amit Kucheria wrote:
> Hi,
>
> I have the following code:
> --------------------------------
> #define NEWLN "\n"
>
> #define MYDBG1 1
> #define MYDEBUG1(fmt, args...) \
> if (MYDBG1) printk(KERN_DEBUG fmt NEWLN, ## args )
> --------------------------------
>
> What is intended is that, using MYDEBUG1 as:
> MYDEBUG1("some debugging info %d %x", var1, var2);
>
> should produce:
> printk(KERN_DEBUG "some debugging info %d %x" "\n", var1, var2);
>
> which will become:
> printk(KERN_DEBUG "some debugging info %d %x\n", var1, var2);
>
> thus saving a valuable "\n" and sparing me from RSI !!!!! ;)
>
> But the above macro doesn't do the job. It produces the following:
> if (1 ) printk("<7>" "some debugging info %d %x" , var1, var2);
>
> Any pointers to bugs?
> BTW, this works in userspace but not in kernelspace.
>
> ciao,
> Amit
>
>
--
-Pradeep
-----------------------------------
Let us be the change, we wish to see in this world.
--- Mahatma Gandhi
-----------------------------------
Pradeep Jagannath
pradeep@it.iitb.ernet.in
http://www.it.iitb.ernet.in/~pradeep
-----------------------------------
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