On Mon, 4 Feb 2002, A. Ramesh wrote:
> I am not sure why the kernel allocates 15 more bytes when it creates a fragment packet. The piece of kernel code which does the memory allocated for the new fragment is as follows:
>
> if ((skb2 = alloc_skb(len+hlen+dev->hard_header_len+15,GFP_ATOMIC)) == NULL) {
> NETDEBUG(printk(KERN_INFO "IP: frag: no memory for new fragment!\n"));
> err = -ENOMEM;
> goto fail;
> }
>
> -Ramesh
Its for word (2-byte) alignment of skb i think. See alloc_skb()
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