On Fri, 25 Jan 2002, Swapnil Nagle wrote:
> Hi all,
>
> I want to run a low priority kernel thread, so i did
> something like:
>
> my_thread(){
> .
> .
> .
> daemonize();
> current->nice = 20;
> for(;;){
> current->state = TASK_INTERRUPTIBLE;
> schedule();
> .
> . <==== control never comes here
> .
> }
> }
>
> The problem is that schedule does not return. So the code after schedule() never gets executed. The control returns
> if schedule_timeout() is used.
>
> What could be the problem?
hmmm. Maybe because you set the task state to TASK_INTERRUPTIBLE and no
one wakes it up?
regards
Roberto
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