As you know, there are 2 different open() calls: a) open(char *path, int flags, mode_t mode) b) open(char *path, int flags) How does the compiler distinguish between two? I guess stdarg stuff cannot be used, as we should know beforehand the number and types of the arguments. they don't look like macros (never mentioned anywhere). Or function overloading in C, I don't think so :) Anybody knows what fopen() does call? open() in the C library or directly the system call SYS_open, using syscall(). Thanks in advance... -- Muzaffer Ozakca Researcher/Software Engineer - muzaffer.ozakca@bilten.metu.edu.tr TUBITAK-Bilten-ODTU - Communication Systems and Comp. Networks Group ODTU, Ankara, Turkey http://www.bilten.metu.edu.tr/ tel: +90-312-210 1311 -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ IRC Channel: irc.openprojects.net / #kernelnewbies Web Page: http://www.kernelnewbies.org/
