Hi all,
I saw this code in /include/asm-i386/unistd.h
can any one please explain me the code
i m not good in assembly language but i can understand if u explain me.
as far as i understood
line 5 calls the interrupt 0x80
in line 6 the return value of the system call which is stored in the
accumulater is assigned to __res
what does line no 7 means.I think it takes the position of the system call in
the sys_call_table.But i dont understand what does that "0" means and
what exactly happens when line 7 is executed.
Simply stating how a particular system call is called when this code is
executed.
1 #define _syscall0(type,name) \
2 type name(void) \
3 { \
4 long __res; \
5 __asm__ volatile ("int $0x80" \
6 : "=a" (__res) \
7 : "0" (__NR_##name)); \
8 __syscall_return(type,__res); \
9 }
thanks and regards,
mohan.
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