As the short subject line informs you I have 3 network cards and 2 internet connections eth0 - default internet eth1 - localnet eth2 - secondary internet (used mainly for http) I wrote a script that puts up some portforwarding: --------------------------- #!/bin/bash if [ "$4" ]; then PROTO=$4 else PROTO="tcp" fi IP=`ifconfig eth0 | grep inet | cut -d: -f2 | cut -d\ -f1` IP2=`ifconfig eth2 | grep inet | cut -d: -f2 | cut -d\ -f1` iptables -A PREROUTING -t nat -d $IP -p $PROTO -m $PROTO --dport $1 -j DNAT --to-destination $2:$3 iptables -A PREROUTING -t nat -d $IP2 -p $PROTO -m $PROTO --dport $1 -j DNAT --to-destination $2:$3 iptables -A FORWARD -d $2 -i eth0 -o eth1 -p $PROTO -m $PROTO --dport $3 -j ACCEPT iptables -A FORWARD -d $2 -i eth2 -o eth1 -p $PROTO -m $PROTO --dport $3 -j ACCEPT --------------------------- basically that would setup portforwarding typing: add_portforward 6000 192.168.0.5 21 that would portforward port 6000 to 192.168.0.5:21 it all works fine for my main ip. but when it comes to the second ip . *gee* it doesn't know how to handle it.. my qualified guess says the signal going back to the initiator of the connection is going through eth0 instead of eth2 ..thus not working. What am I missing ? my eth0 is setup using dhcpcd and my eth2 is setup using static ip plus these iproute2 settings: ip rule add from 0/0 dev eth2 table bostream ip rule add from $BOSTREAMIP table bostream ip rule add fwmark 0x02 lookup bostream ip route add default via $BOSTREAMGW dev $BOSTREAMIF table bostream ip route add 192.168.0.0 dev $INTIF table bostream So to clarify things. What I want to achieve is for a connection initated from the outside (eth2) to be forwarded to a local host (via eth1). And all the answers from this host should go back (via eth1) and be forwarded out to the originating server (via eth2) instead of being stopped 'cause of reaching the server with the ip of eth0. .... eehm.. when I think of it, that didn't really come out any more comprehensive :) sure hope anyone can help Tommy ----------- 2 is the only even prime-number therefore it is odd
