Hi all,
I'm using ip route get to debug a routing probelm and I get:
root@fw-euronet argo # ip route get 192.168.254.10
192.168.254.10 dev eth0 src 192.168.254.1
cache mtu 1500 advmss 1460
root@fw-euronet argo # ip route get 192.168.254.10 from 192.168.5.2
RTNETLINK answers: Invalid argument
What does really mean "RTNETLINK answers: Invalid argument",
I get the same error w/
root@fw-euronet argo # ip route get 192.168.254.10 iif tun0
RTNETLINK answers: Invalid argument
My rules are:
root@fw-euronet argo # ip ru li
0: from all lookup local
30: from all iif tun0 lookup adsl
38: from 192.168.254.10 lookup hdsl
40: from 217.58.51.160/27 lookup hdsl
41: from 81.121.243.248/30 lookup adsl
52: from all iif eth0 lookup adsl
53: from all iif eth2 lookup adsl
32766: from all lookup main
32767: from all lookup default
where you can see that tun0, where 192.168.5.0/24 is, should look table adsl
that is define this way:
root@fw-euronet argo # ip ro ls table adsl
81.121.243.248/30 dev eth3 scope link src 81.121.243.250
217.58.51.160/27 dev eth1 scope link src 217.58.51.162
192.168.5.0/24 dev tun0 scope link
192.168.1.0/24 dev eth2 scope link src 192.168.1.1
192.168.254.0/24 dev eth0 scope link src 192.168.254.1
default via 81.121.243.249 dev eth3
TYA
sandro
*:-)
--
Sandro Dentella *:-)
e-mail: sandro@xxxxxxxx
http://www.tksql.org TkSQL Home page - My GPL work
