On Tue, May 24, 2016 at 11:01:21PM -0400, Waiman Long wrote:
> On 05/24/2016 10:27 AM, Peter Zijlstra wrote:
> >Introduce smp_acquire__after_ctrl_dep(), this construct is not
> >uncommen, but the lack of this barrier is.
> >
> >Signed-off-by: Peter Zijlstra (Intel)<peterz@xxxxxxxxxxxxx>
> >---
> > include/linux/compiler.h | 14 ++++++++++----
> > ipc/sem.c | 14 ++------------
> > 2 files changed, 12 insertions(+), 16 deletions(-)
> >
> >--- a/include/linux/compiler.h
> >+++ b/include/linux/compiler.h
> >@@ -305,20 +305,26 @@ static __always_inline void __write_once
> > })
> >
> > /**
> >+ * smp_acquire__after_ctrl_dep() - Provide ACQUIRE ordering after a control dependency
> >+ *
> >+ * A control dependency provides a LOAD->STORE order, the additional RMB
> >+ * provides LOAD->LOAD order, together they provide LOAD->{LOAD,STORE} order,
> >+ * aka. ACQUIRE.
> >+ */
> >+#define smp_acquire__after_ctrl_dep() smp_rmb()
> >+
> >+/**
> > * smp_cond_acquire() - Spin wait for cond with ACQUIRE ordering
> > * @cond: boolean expression to wait for
> > *
> > * Equivalent to using smp_load_acquire() on the condition variable but employs
> > * the control dependency of the wait to reduce the barrier on many platforms.
> > *
> >- * The control dependency provides a LOAD->STORE order, the additional RMB
> >- * provides LOAD->LOAD order, together they provide LOAD->{LOAD,STORE} order,
> >- * aka. ACQUIRE.
> > */
> > #define smp_cond_acquire(cond) do { \
> > while (!(cond)) \
> > cpu_relax(); \
> >- smp_rmb(); /* ctrl + rmb := acquire */ \
> >+ smp_acquire__after_ctrl_dep(); \
> > } while (0)
> >
> >
>
> I have a question about the claim that control dependence + rmb is
> equivalent to an acquire memory barrier. For example,
>
> S1: if (a)
> S2: b = 1;
> smp_rmb()
> S3: c = 2;
>
> Since c is independent of both a and b, is it possible that the cpu
> may reorder to execute store statement S3 first before S1 and S2?
The CPUs I know of won't do, nor should the compiler, at least assuming
"a" (AKA "cond") includes READ_ONCE(). Ditto "b" and WRITE_ONCE().
Otherwise, the compiler could do quite a few "interesting" things,
especially if it knows the value of "b". For example, if the compiler
knows that b==1, without the volatile casts, the compiler could just
throw away both S1 and S2, eliminating any ordering. This can get
quite tricky -- see memory-barriers.txt for more mischief.
The smp_rmb() is not needed in this example because S3 is a write, not
a read. Perhaps you meant something more like this:
if (READ_ONCE(a))
WRITE_ONCE(b, 1);
smp_rmb();
r1 = READ_ONCE(c);
This sequence would guarantee that "a" was read before "c".
Thanx, Paul
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