Hi,
The kexec system call seems to require that the vmlinuz loading address is
aligned to a page boundary. 4096 bytes is a fairly common page size, but
perhaps not the only possibility? Does kexec require additional alignments?
Fredrik
Signed-off-by: Fredrik Noring <noring@xxxxxxxxxx>
--- a/arch/mips/boot/compressed/calc_vmlinuz_load_addr.c
+++ b/arch/mips/boot/compressed/calc_vmlinuz_load_addr.c
@@ -44,12 +44,8 @@ int main(int argc, char *argv[])
vmlinux_size = (uint64_t)sb.st_size;
vmlinuz_load_addr = vmlinux_load_addr + vmlinux_size;
- /*
- * Align with 16 bytes: "greater than that used for any standard data
- * types by a MIPS compiler." -- See MIPS Run Linux (Second Edition).
- */
-
- vmlinuz_load_addr += (16 - vmlinux_size % 16);
+ /* The kexec system call requires page alignment. */
+ vmlinuz_load_addr += (4096 - vmlinux_size % 4096);
printf("0x%llx\n", vmlinuz_load_addr);
