On Wed, Dec 20, 2017 at 06:11:04PM +0300, Yuri Frolov wrote:
> Hi, James
>
> On 12/16/2017 02:28 AM, James Hogan wrote:
> > On Fri, Dec 15, 2017 at 05:05:12PM +0300, Yuri Frolov wrote:
> >> Hi, James
> >>
> >> On 12/14/2017 06:21 PM, James Hogan wrote:
> >>> Hi Yuri,
> >>>
> >>> On Thu, Dec 14, 2017 at 06:03:11PM +0300, Yuri Frolov wrote:
> >>>> Hi, James.
> >>>>
> >>>> Do I understand correctly, that in case of CONFIG_EVA=y, any logical
> >>>> address from 0x00000000 - 0xBFFFFFFF (3G) range accessed from the kernel
> >>>> space is:
> >>>> 1) Unmapped (no TLB translations)
> >>>> 2) Is mapped 1:1 to physical addresses? E.g, readl from 0x20000000 is,
> >>>> in fact a read from physical address 0x20000000? I mean, in legacy
> >>>> memory mapping scheme, logical addresses 0x80000000 - 0xBFFFFFFF in
> >>>> kernel space were being translated to the physical addresses from the
> >>>> low 512Mb (phys 0x00000000 - 0x20000000), no such bits stripping or
> >>>> something for EVA, the mapping is 1:1?
> >>> That depends on the EVA configuration. The hardware is fairly flexible
> >>> (which is both useful and painful - making supporting EVA from
> >>> multiplatform kernels particularly awkward), but that is one possible
> >>> configuration.
> >>>
> >>> E.g. ideally you probably want to keep seg5 (0x00000000..0x3FFFFFFF)
> >>> MUSK (TLB mapped for user & kernel) so that null dereferences from
> >>> kernel code are safely caught, but that costs you 1GB of directly
> >>> accessible physical address space from kernel mode.
> >> So, do I understand correctly, that provided we have these TLB entries
> >> in kernel,
> >>
> >> Index: 71 pgmask=16kb va=c0038000 asid=00
> >> [ri=0 xi=0 pa=200e0000 c=2 d=1 v=1 g=1] [ri=0 xi=0 pa=00000000
> >> c=0 d=0 v=0 g=1]
> >> Index: 72 pgmask=16kb va=c0040000 asid=00
> >> [ri=0 xi=0 pa=200c0000 c=2 d=1 v=1 g=1] [ri=0 xi=0 pa=200c4000
> >> c=2 d=1 v=1 g=1]
> >>
> >> u32 l;
> >>
> >> l = readl((const volatile void *)(0x200c0000 + 0x20))
> > assuming you have segment5 (0x00000000..0x3FFFFFFF) set to MUSUK, with
> > PA 0 (i.e. direct 1:1 mapping), it'd access PA 0x200c0020, but
> > presumably the segment will be configured to be cached (CCA 3) or cached
> > coherent (CCA 5).
> >
> >> and
> >> l = *(u32 *)(0xc0040000+ 0x20)
> > this will access physical addres 0x200c0020 uncached (CCA 2).
> >
> >> should return the same value?
> > So that would depend I think on whether there is a dirty value in the
> > cache. Possibly not. The cached mapping would see the dirty value. The
> > uncached mapping may see a stale value straight from RAM.
> >
> > Cheers
> > James
> I'm looking at arch/mips/include/asm//mach-malta/kernel-entry-init.h and
> there is a definition for SegCtl2:
>
> /* SegCtl2 */
> li t0, ((MIPS_SEGCFG_MUSUK << MIPS_SEGCFG_AM_SHIFT) | \
> (6 << MIPS_SEGCFG_PA_SHIFT) | \
> (1 << MIPS_SEGCFG_EU_SHIFT)) | \
> (((MIPS_SEGCFG_MUSUK << MIPS_SEGCFG_AM_SHIFT) | \
> (4 << MIPS_SEGCFG_PA_SHIFT) | \
> (1 << MIPS_SEGCFG_EU_SHIFT)) << 16)
>
> it defines, that kernel logical addresses from the range 0x00000000 -
> 0x7fffffff are unmapped (no tlbs) and dictates, that in order to get a
> physical address for any logical addresses from 0x00000000 - 0x3fffffff
> range in kernel space, bits [31:29] of the logical address must be
> changed to 100,
> and (again in kernel space) for any logical addresses from 0x40000000 -
> 0x7fffffff range, bits [31:29] of the logical address must be changed to
> 110, right?
yes, the Malta implementation is slightly ugly as it relies on a
hardware physical memory alias of RAM starting at PA 0x80000000.
>
> What physical addresses will logical addresses 0x00000000 and 0x20000000
> be translated in kernel space?.. logical 0x00000000 --> physical
> 0x80000000, and logical 0x20000000 --> .... 0x80000000 too?
VA 0x20000000 -> PA 0xa0000000, since seg4 and seg5 are 1GB segments, so
its only bits 30 and up that can be changed. I seem to remember the bit
corresponding to bit 29 isn't even writable in the SegCtl2 register.
Does that clarify things?
Cheers
James
> Since we must to change bits [31:29], we have to change bit 29 ('1') in
> logical address 0x200000000 to '0' (since PA for this range is 100).
>
> So, what physical addresses will all logical addresses which have '1' at
> 29 bit be translated, if we define PA as 100 and 110 in SegCtl2? It
> looks like there's no flat translation of logical addresses to physical
> addresses in kernel space, and this is obviously just not correct, there
> is something simple I've been overlooking.
>
> Thank you,
> Yuri
