Hi My question is around physical memory allocation. This is used by VPE1 to enable FXS (analogue telephone ports) support, details: https://dev.openwrt.org/browser/branches/barrier_breaker/target/linux/lantiq/patches-3.10/0152-VPE-extensions.patch?rev=43158 https://forum.openwrt.org/viewtopic.php?id=62696 The command line used by a MIPS based lantiq router (VRX288) at command line: "phym=64M mem=62M vpe1_load_addr=0x83e00000 vpe1_mem=2M" Is it possible to do this by a smoother way? So with removing the phym and mem arguments. I tried the following in the driver. Therefore I changed the command line to "vpe1_load_addr=0x83e00000" (removed phym, mem, and 2M parts). I used this within the driver: reserve_bootmem(load_addr, size, BOOTMEM_DEFAULT). But then I will get a kernel panic at mark_bootmem+0xec/0x120. I have read some about QMA, too. But this needs some additional kernel dependencies. But in general is this useful for this problem? Do you have some idea? What would be a good/beautiful approach? What is the best way to alloc physical continuous public memory? The memory should also accessible without SEGFAULT in userspace and by other drivers. Optional: Is there also a way that is transparent to other drivers and userspace? So that the drivers/userspace see still 64M max memory, but 2M as used. With mmem way the userspace see's 62M max mem. Especially because this bug, WIFI doesn't work with 62M :( https://bugzilla.kernel.org/show_bug.cgi?id=110091 Thanks :) Best regards Stefan
