On Monday 19 January 2009, Atsushi Nemoto wrote: > The bcount is greater than 0 and less than or equal to 0x10000. > Thus '(bcount & 0xffff) == 0x0000' can be simplified as 'bcount == 0x10000'. > > Suggested-by: Sergei Shtylyov <sshtylyov@xxxxxxxxxxxxx> > Signed-off-by: Atsushi Nemoto <anemo@xxxxxxxxxxxxx> applied
