David Daney writes:That is evidently what you have to do on i386. MIPS gives the right answer without faulting (i.e. hitting the break 7).
> Andrew Haley wrote:
> > MIPS div instructions never trap. However I think that GCC always emits > things like this when it cannot determine that the divisor is non zero:
> > div $0,$17,$16
> bne $16,$0,1f
> nop
> break 7
> 1:
> >
> >No, there's no reason not to do it. You'll have to write some hairy
> >code to satisfy all the rules, though.
> >
> What are the rules? Are they more complicated then throw an > ArithmeticException when the divisor is zero?
Yes. You also have to do
if (dividend == (jint) 0x80000000L && divisor == -1)
return dividend;
and not throw an exception.
David Daney.
