On Wed, Apr 02, 2003 at 05:02:08PM -0800, Mike K. wrote:
> extern __inline__ void atomic_add(int i, atomic_t * v)
> {
> unsigned long temp;
>
> __asm__ __volatile__(
> "1: ll %0, %1 # atomic_add\n"
> " addu %0, %2 \n"
> " sc %0, %1 \n"
> " beqz %0, 1b \n"
> : "=&r" (temp), "=m" (v->counter)
> : "Ir" (i), "m" (v->counter));
> }
>
>
> Beginner questions on the above code:
> 1. what is %0 %1 %2?
> 2. what is the details meaning of the last two line of the above code?
%0 stands for the 0th operand of the asm statement, that is the temp
variable, %1 for the first that is v->counter, %2 for the second that is
the variable i. In the strings like "=&r" the = means that the argument
will be assigned to, r means the argument / result is to be passed in a
register (%0 will then be replaced by gcc with that register) and m
means some memory location, gcc will then replace %1 with that memory
location. "Ir" means gcc can pass the variable i in either a register
(that's the r) or as a 16-bit constant (the I). Again %3 will be
replaced with whatever gcc deciedes to pass here. All the output
operands are listed after the first colon - and be marked with a = sign;
the input operands are listed after the second colon. After a third
colon all registers that get destroyed by a piece of inline assembly
can be listed like :"$5","$6" but we don't need that here.
> 3. Very thanksful if you can comment each line with detail description for
> me, thanks a lot!
Your basic spinlock described in the R4000 manual from 10 years ago :-)
Ralf
