hwmon/w83627hf pwm_freq support

[com.ea at tinet.org (Carlos Olalla Martínez)]

> > +	u8 i;
> > +	/* Only 5 dividers (1 2 4 8 16)... Search for the nearest available
frequency */
> > +	for (i = 0; i < 5; i++) {
> > +		if (val > (((W83627HF_BASE_PWM_FREQ >> i) + (W83627HF_BASE_PWM_FREQ
>> (i+1))) / 2))
> > +			break;
> > +	}
> > +	return i;
> > +}

> This could return with i = 5, which isn't correct.

Hi Jean,

I dont agree on your statement; I think

for (i = 0; i < 5; i++)

is the same as

for (i = 0; i <= 4; i++)

so maximum i returned is 4. Am I wrong??

Carlos