> > newrem=reminder*10
> >
> > if newrem<10000 then
> > print("0%d",reminder);
> > else
> > print(reminder);
> > end if
>
> This is strange... They do a special case what <10000 but not when <1000
> for example. So I guess that 1.0023 would appear ad 1.023? And I don't
> see the benefit of *10.
Its only multiplied to perform the test. Printing is done with original
numbers. I think its only some kind of padding, but next +600 is strange.
> > if newrem<10000 then
> > print("0%d",reminder);
> > else
> > print( (reminder+600) );
> > end if
>
> Even stranger. I cannot see the idea behind the +600.
Same problem.
> What does the print function exactly? Print the numerical value of eax?
See the end.
> > print((reminderofthis*256+quotientofthis)+400)
>
> This goes completely weird. It's not even monotonic!
I guess it should be swapped
so xchg al,ah is missing but again the purporse is mysterious.
> > 0000AC66 58 pop ax ;ax holds reminder
> > 0000AC67 B30A mov bl,0xa
> > 0000AC69 F6F3 div bl ;do reminder /10, AH reminder
> > 0000AC6B 660FB7C0 movzx eax,ax ;extend to 32bit
> > 0000AC6F 6605740E0000 add eax,0xe74 ;add 3700
> > 0000AC75 E84DCE call 0x7ac5 ;call print
>
> Seems clear (unless your explanations don't match the code, I don't know
> x86 asm enough to tell). But what does the print function exactly?
00007AC5 6633D2 xor edx,edx ;zero edx
00007AC8 66B90A000000 mov ecx,0xa ;10
00007ACE 66F7F1 div ecx ;divide
00007AD1 660BC0 or eax,eax ;is eax zero
00007AD4 7405 jz 0x7adb ;if so we are at the end.
00007AD6 52 push dx ;reminder in EDX
00007AD7 E8EBFF call 0x7ac5 ;recursively call us again EAX is
;quotient
00007ADA 5A pop dx ;restore digit
00007ADB 8AC2 mov al,dl ;al=dl
00007ADD 0C30 or al,0x30 ;
00007ADF 268805 mov [es:di],al ;write one digit.
00007AE2 47 inc di ;inc pointer
00007AE3 C3 ret
It simply convert number stored in eax to string pointed by es:di register
pair. Its recursive to get right order.
sprintf(esdi,"%d",eax);
Regards
Rudolf
