I doesn't compile with "make users".
I'm using kernle 2.6.1 and trying to compile lm_sensors 2.8.3 with make users,
but I get this:
/lib/modules/2.6.1/build/include/linux/highmem.h:87:36: macro
"clear_user_page" requires 3 arguments, but only 2 given
/lib/modules/2.6.1/build/include/linux/highmem.h:119:41: macro
"copy_user_page" requires 4 arguments, but only 3 given
cat kernel/include/sensors.h.template > kernel/include/sensors.h
awk '/SENSORS SYSCTL START/,/SENSORS SYSCTL END/' kernel/chips/*.c >>
kernel/include/sensors.h
echo '#endif' >> kernel/include/sensors.h
gcc -M -MG -I. -Ikernel/include -I/usr/local/include -Wall -O2
-march=athlon-xp -mcpu=athlon-xp -O3 -pipe -fomit-frame-pointer
prog/sensors/chips.c | \
sed -e 's@^\(.*\)\.o:@prog/sensors/chips.rd prog/sensors/chips.ro:
Makefile '`dirname prog/sensors/chips.rd`/Module.mk' @' >
prog/sensors/chips.rd
gcc -M -MG -I. -Ikernel/include -I/usr/local/include -Wall -O2
-march=athlon-xp -mcpu=athlon-xp -O3 -pipe -fomit-frame-pointer lib/proc.c |
\
sed -e 's@^\(.*\)\.o:@lib/proc.ad lib/proc.ao: Makefile '`dirname
lib/proc.ad`/Module.mk' @' > lib/proc.ad
gcc -M -MG -I. -Ikernel/include -I/usr/local/include -Wall -O2
-march=athlon-xp -mcpu=athlon-xp -O3 -pipe -fomit-frame-pointer lib/chips.c |
\
sed -e 's@^\(.*\)\.o:@lib/chips.ad lib/chips.ao: Makefile '`dirname
lib/chips.ad`/Module.mk' @' > lib/chips.ad
gcc -M -MG -I. -Ikernel/include -I/usr/local/include -fpic -Wall -O2
-march=athlon-xp -mcpu=athlon-xp -O3 -pipe -fomit-frame-pointer lib/proc.c |
\
sed -e 's@^\(.*\)\.o:@lib/proc.ld lib/proc.lo: Makefile '`dirname
lib/proc.ld`/Module.mk' @' > lib/proc.ld
gcc -M -MG -I. -Ikernel/include -I/usr/local/include -fpic -Wall -O2
-march=athlon-xp -mcpu=athlon-xp -O3 -pipe -fomit-frame-pointer lib/chips.c |
\
sed -e 's@^\(.*\)\.o:@lib/chips.ld lib/chips.lo: Makefile '`dirname
lib/chips.ld`/Module.mk' @' > lib/chips.ld
make: *** No rule to make target `users'. Stop.
I've got Slackware 9.1. How can it possible I cannot compile
lm_sensors? I tryed with a lot of version but it's very complicated.
A linux user
