Re: [PATCH] xfs: test mkfs.xfs sizing of internal logs that

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On Tue, May 24, 2022 at 05:32:50PM -0700, Darrick J. Wong wrote:
> On Wed, May 25, 2022 at 10:24:13AM +1000, Dave Chinner wrote:
> > On Tue, May 24, 2022 at 04:49:30PM -0700, Darrick J. Wong wrote:
> > > On Wed, May 25, 2022 at 09:44:26AM +1000, Dave Chinner wrote:
> > > > On Tue, May 24, 2022 at 12:52:57PM -0700, Darrick J. Wong wrote:
> > > > > From: Darrick J. Wong <djwong@xxxxxxxxxx>
> > > > > 
> > > > > This is a regression test that exercises the mkfs.xfs code that creates
> > > > > log sizes that are very close to the AG size when stripe units are in
> > > > > play and/or when the log is forced to be in AG 0.
> > > > > 
> > > > > Signed-off-by: Darrick J. Wong <djwong@xxxxxxxxxx>
> > > > > ---
> > > > >  tests/xfs/843     |   56 +++++++++++++++++++++++++++++++++++++++++++++++++++++
> > > > >  tests/xfs/843.out |    2 ++
> > > > >  2 files changed, 58 insertions(+)
> > > > >  create mode 100755 tests/xfs/843
> > > > >  create mode 100644 tests/xfs/843.out
> > > > > 
> > > > > diff --git a/tests/xfs/843 b/tests/xfs/843
> > > > > new file mode 100755
> > > > > index 00000000..3384b1aa
> > > > > --- /dev/null
> > > > > +++ b/tests/xfs/843
> > > > > @@ -0,0 +1,56 @@
> > > > > +#! /bin/bash
> > > > > +# SPDX-License-Identifier: GPL-2.0
> > > > > +# Copyright (c) 2022 Oracle.  All Rights Reserved.
> > > > > +#
> > > > > +# FS QA Test 843
> > > > > +#
> > > > > +# Now that we've increased the default log size calculation, test mkfs with
> > > > > +# various stripe units and filesystem sizes to see if we can provoke mkfs into
> > > > > +# breaking.
> > > > > +#
> > > > > +. ./common/preamble
> > > > > +_begin_fstest auto mkfs
> > > > > +
> > > > > +_cleanup()
> > > > > +{
> > > > > +	cd /
> > > > > +	rm -r -f $tmp.* $testfile
> > > > > +}
> > > > 
> > > > I'd omit this completely.
> > > > 
> > > > > +# real QA test starts here
> > > > > +
> > > > > +# Modify as appropriate.
> > > > > +_supported_fs xfs
> > > > > +_require_test
> > > > > +
> > > > > +testfile=$TEST_DIR/a
> > > > > +rm -f $testfile
> > > > > +
> > > > > +test_format() {
> > > > > +	local tag="$1"
> > > > > +	shift
> > > > > +
> > > > > +	echo "$tag" >> $seqres.full
> > > > > +	$MKFS_XFS_PROG $@ -d file,name=$testfile &>> $seqres.full
> > > > > +	local res=$?
> > > > > +	test $res -eq 0 || echo "$tag FAIL $res" | tee -a $seqres.full
> > > > 
> > > > What breakage are you trying to provoke? Just the log size
> > > > calculation? If so, why do we need to actually write the filesystem
> > > > to disk? Won't "-N" still calculate everything and fail if it's
> > > > broken or quit with success without needing to write anything to
> > > > disk?
> > > 
> > > It will, but...
> > > 
> > > > > +}
> > > > > +
> > > > > +# First we try various small filesystems and stripe sizes.
> > > > > +for M in `seq 298 302` `seq 490 520`; do
> > > > > +	for S in `seq 32 4 64`; do
> > > > > +		test_format "M=$M S=$S" -dsu=${S}k,sw=1,size=${M}m
> > > > > +	done
> > > > > +done
> > > > > +
> > > > > +# log so large it pushes the root dir into AG 1
> > > > > +test_format "log pushes rootdir into AG 1" -d agcount=3200,size=6366g -lagnum=0
> > > 
> > > ...this particular check in mkfs only happens after we allocate the root
> > > directory, which an -N invocation doesn't do.
> > 
> > Ok, so for this test can we drop the -N? We don't need to do 30 IOs
> > and write 64MB logs for every config we test - I think there's ~35 *
> > 8 invocations of test_format in the loop above before we get here...
> > 
> > Also, why do we need a 6.3TB filesystem with 2.1GB AGs and a 2GB log
> > to trigger this? That means we have to write 2GB to disk, plus
> > ~20,000 write IOs for the AG headers and btree root blocks before we
> > get to the failure case, yes?
> 
> So long as the test filesystem is itself XFS and a reasonably new
> vintage, mkfs.xfs will call FALLOC_FL_ZERO_RANGE to zero the log, which
> means we're not writing 2GB to storage with every format.

Oh, cycle = XLOG_INIT_CYCLE short-cuts stamping the head/tail LSNs
into every sector of the log. Ok, so we don't have to write the log
in this case, just issue 20,000 IOs to write out the AG headers...

> > Why not just exercise the failure case with something like this:
> > 
> > # mkfs.xfs -d agcount=2,size=64M -l size=8180b,agnum=0 -d file,name=test.img
> > meta-data=test.img               isize=512    agcount=2, agsize=8192 blks
> >          =                       sectsz=512   attr=2, projid32bit=1
> >          =                       crc=1        finobt=1, sparse=1, rmapbt=0
> >          =                       reflink=1    bigtime=0 inobtcount=0
> > data     =                       bsize=4096   blocks=16384, imaxpct=25
> >          =                       sunit=0      swidth=0 blks
> > naming   =version 2              bsize=4096   ascii-ci=0, ftype=1
> > log      =internal log           bsize=4096   blocks=8180, version=2
> >          =                       sectsz=512   sunit=0 blks, lazy-count=1
> > realtime =none                   extsz=4096   blocks=0, rtextents=0
> > mkfs.xfs: root inode created in AG 1, not AG 0
> > # echo $?
> > 1
> > #
> > 
> > Otherwise I don't exactly understand what this specific case is
> > supposed to be testing, so maybe some more explaining is necessary?
> 
> To be honest, I hadn't thought of that; this test encodes all the weird
> scenarios that Eric and I came up with over many hours of bluejeans
> chatting to see if we could trip up all the mkfs log sizing code and
> related fixes.

*nod*. I figured it was probably either an oversight or me being
incredibly stupid again. EIther way, it looks like the only way we
can trip over this is incredibly contrived mkfs configs, so I'd
argue that the smaller, faster option is just as good as the bigger,
slower one...

Cheers,

Dave.
-- 
Dave Chinner
david@xxxxxxxxxxxxx



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