Re: [PATCH] xfs: allocate sector sized IO buffer via page_frag_alloc

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On Wed, Feb 27, 2019 at 07:45:50AM +1100, Dave Chinner wrote:
> On Tue, Feb 26, 2019 at 05:33:04PM +0800, Ming Lei wrote:
> > On Tue, Feb 26, 2019 at 03:58:26PM +1100, Dave Chinner wrote:
> > > On Mon, Feb 25, 2019 at 07:27:37PM -0800, Matthew Wilcox wrote:
> > > > On Tue, Feb 26, 2019 at 02:02:14PM +1100, Dave Chinner wrote:
> > > > > > Or what is the exact size of sub-page IO in xfs most of time? For
> > > > > 
> > > > > Determined by mkfs parameters. Any power of 2 between 512 bytes and
> > > > > 64kB needs to be supported. e.g:
> > > > > 
> > > > > # mkfs.xfs -s size=512 -b size=1k -i size=2k -n size=8k ....
> > > > > 
> > > > > will have metadata that is sector sized (512 bytes), filesystem
> > > > > block sized (1k), directory block sized (8k) and inode cluster sized
> > > > > (32k), and will use all of them in large quantities.
> > > > 
> > > > If XFS is going to use each of these in large quantities, then it doesn't
> > > > seem unreasonable for XFS to create a slab for each type of metadata?
> > > 
> > > 
> > > Well, that is the question, isn't it? How many other filesystems
> > > will want to make similar "don't use entire pages just for 4k of
> > > metadata" optimisations as 64k page size machines become more
> > > common? There are others that have the same "use slab for sector
> > > aligned IO" which will fall foul of the same problem that has been
> > > reported for XFS....
> > > 
> > > If nobody else cares/wants it, then it can be XFS only. But it's
> > > only fair we address the "will it be useful to others" question
> > > first.....
> > 
> > This kind of slab cache should have been global, just like interface of
> > kmalloc(size).
> > 
> > However, the alignment requirement depends on block device's block size,
> > then it becomes hard to implement as genera interface, for example:
> > 
> > 	block size: 512, 1024, 2048, 4096
> > 	slab size: 512*N, 0 < N < PAGE_SIZE/512
> > 
> > For 4k page size, 28(7*4) slabs need to be created, and 64k page size
> > needs to create 127*4 slabs.
> 
> IDGI. Where's the 7/127 come from?
> 
> We only require sector alignment at most, so as long as each slab
> object is aligned to it's size, we only need one slab for each block
> size.

Each slab has fixed size, I remembered that you mentioned that the meta
data size can be 512 * N (1 <= N <= PAGE_SIZE / 512).

https://marc.info/?l=linux-fsdevel&m=155115014513355&w=2


Thanks, 
Ming



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