On Mon, Nov 5, 2018 at 12:48 PM Dave Chinner <david@xxxxxxxxxxxxx> wrote: > > On Mon, Nov 05, 2018 at 11:15:34AM +0100, Jan Tulak wrote: > > On Fri, Nov 2, 2018 at 11:34 PM Dave Chinner <david@xxxxxxxxxxxxx> wrote: > > > > > > On Fri, Nov 02, 2018 at 12:43:18PM +0100, Jan Tulak wrote: > > > > On Fri, Nov 2, 2018 at 2:36 AM Dave Chinner <david@xxxxxxxxxxxxx> wrote: > > > > > On Thu, Nov 01, 2018 at 12:01:28PM +0100, Jan Tulak wrote: > > > > > However, it's is the same change as what you originally posted to a > > > > > > > > Yes, it is the same thing, with changes where I found something > > > > misaligned on top. > > > > > > > > > git tree, then it needs revision. basically, most of the change was > > > > > converting vertically aligned function call parameters to use tabs, > > > > > and that broke the vertical alignment. > > > > > > > > It is "s/ /\t/" limited to the beginning of the line. > > > > > > You mean 's/^ /\t/'? > > > > Yes, but in multiple iterations to get \t, \t\t, \t\t\t, ... > > Which is handled by this regex: 's/^\(\t*\)* /\1\t/' > > In this case, I'm using "*", which means "match zero or more of the > preceding expression" - which in this case is \t. That regex is > enclosed in \(...\) to group the result, which is then back > referenced in the output expression by \1 (first group backref). > > Regexes are extremely and flexible once you've learnt how the > multiple object matching rules work. I know. But I don't see how your regex would take the number of four-space groups and inserted the same number of \t, which is what I was trying to do and AFAIK there is no way to do it with sed. I know it could be done with awk, but writing it would take more time for me than re-running s/^ /\t\t/ with a manually changed number of occurrences, from one to say 5 levels (or until I stop getting any changes). Cheers, Jan
