https://bugzilla.kernel.org/show_bug.cgi?id=201453 --- Comment #5 from Eric Sandeen (sandeen@xxxxxxxxxxx) --- So zorro correctly points out that the big vs little endian certainly should not matter for this u8. What does matter is the signed type, because getbitval is doing tricks to try to handle sign extension and it does it differently for big vs. little endian: if (getbit_l(p, bit + i)) { /* If the last bit is on and we care about sign * bits and we don't have a full 64 bit * container, turn all bits on between the * sign bit and the most sig bit. */ /* handle endian swap here */ #if __BYTE_ORDER == LITTLE_ENDIAN if (i == 0 && signext && nbits < 64) rval = (~0ULL) << nbits; rval |= 1ULL << (nbits - i - 1); #else if ((i == (nbits - 1)) && signext && nbits < 64) rval |= ((~0ULL) << nbits); rval |= 1ULL << (nbits - i - 1); #endif Switching it to FLDT_UINT8D makes "signext" false so none of this happens, but that's papering over the underlying bug with signed types. The bug seems to be the test for if ((i == (nbits - 1)) ...) - this is testing the last / rightmost bit in the number, which is /not/ the MSB. But I cannot seem to wrap my head around the right way to fix it, yet. -- You are receiving this mail because: You are watching the assignee of the bug.
