Hi Mahesh, On Wed, Sep 5, 2012 at 2:45 PM, Mahesh Palivela <maheshp@xxxxxxxxxxx> wrote: > On 09/04/2012 01:55 PM, Johannes Berg wrote: >> >> On Tue, 2012-09-04 at 08:55 +0530, Mahesh Palivela wrote: >>> + left_end_freq -= MHZ_TO_KHZ(10); >>> + right_end_freq -= MHZ_TO_KHZ(10); >> >> >> Hmm? Shouldn't you add 10 MHz to the lower end, if anything? >> > > Nope. For example 80 MHz BW, take channel 36, 40, 44 and 48. Center freq > value is chan 42. so left end will be chan 34 and right end will be chan 50. > so I am subtracting 10MHz on both ends to get chan 36 and 48 Surely if you subtract 10MHz from chan 34, you'd end up with chan 32, right? Thanks, -- Julian Calaby Email: julian.calaby@xxxxxxxxx Profile: http://www.google.com/profiles/julian.calaby/ .Plan: http://sites.google.com/site/juliancalaby/ -- To unsubscribe from this list: send the line "unsubscribe linux-wireless" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
