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Re: problem on ACS

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On Sat, Jul 30, 2011 at 4:17 AM, Christian Lamparter
<chunkeey@xxxxxxxxxxxxxx> wrote:
> Wait a sec... I guess you misunderstood my post about the cut-off.
> I meant that you can cut of at the bottom by using log2(max(1, val)).
> This ensures that the log2 will always be >= 0 anyway. In fact log2(1) = 0.

I get that now, but my point was that we also had to cap it for a
higher value too. We now restrict the input to values within the data
type and also ensure log2 will always be >= 0.

  Luis
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