On Wed, 2010-02-17 at 19:38 +0100, okias wrote:
> You have probably right, but when I use my testing program:
>
> #include <stdio.h>
> main() {
> int a;
> printf("%i\n", a);
> a |= 22;
> printf("%i\n", a);
> }
>
> Output is:
> 0
> 22
>
> it look correct to me
That's what I get if compiling for x86_64. If compiling for i386, I get
1258024948
1258024950
It just happens that 0 is on the stack where the variable is allocated,
perhaps as a leftover from another call that used that area on the
stack.
No C standard says that automatic variables are initialized. And
indeed, they are not!
gcc will warn about it with -Wall
Please let's stop this discussion now, as it doesn't belong to the
linux-wireless mailing list.
--
Regards,
Pavel Roskin
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