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Re: Divide error in minstrel_ht_get_tp_avg()

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On Sat, Aug 21, 2021 at 01:14:34PM +0200, Oleksandr Natalenko wrote:
> > > So, it seems `minstrel_ht_avg_ampdu_len()` can return 0, which is not
> > > really legitimate.
> > > 
> > > Looking at `minstrel_ht_avg_ampdu_len()`, I see the following:
> > > 
> > > ```
> > > 16:#define MINSTREL_SCALE  12
> > > ...
> > > 18:#define MINSTREL_TRUNC(val) ((val) >> MINSTREL_SCALE)
> > > ```
> > > 
> > > ```
> > > 
> > >  401 static unsigned int
> > >  402 minstrel_ht_avg_ampdu_len(struct minstrel_ht_sta *mi)
> > >  403 {
> > > 
> > > ...
> > > 
> > >  406     if (mi->avg_ampdu_len)
> > >  407         return MINSTREL_TRUNC(mi->avg_ampdu_len);
> > > 
> > > ```
> > > 
> > > So, likely, `mi->avg_ampdu_len` is non-zero, but it's too small, hence
> > > right bitshift makes it zero.
(...)
> I've also found out that this happens exactly at midnight, IOW, at 00:00:00. 
> Not every midnight, though.
> 
> Does it have something to do with timekeeping? This is strange, I wouldn't 
> expect kernel to act like that. Probably, some client sends malformed frame? 
> How to find out?

Well, in minstrel_ht_update_stats() at line 1006 avg_ampdu_len is
explicitly set to zero. And this seems to be called based on timing
criteria from minstrel_ht_tx_status() so this could confirm your
experience.  Thus there is some inconsistency there.

Willy



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