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Re: [RFC/RFT] mac80211: Switch to a virtual time-based airtime scheduler

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On 2019-04-10 04:41, Toke Høiland-Jørgensen wrote:
Yibo Zhao <yiboz@xxxxxxxxxxxxxx> writes:

On 2019-04-04 16:31, Toke Høiland-Jørgensen wrote:
Yibo Zhao <yiboz@xxxxxxxxxxxxxx> writes:

On 2019-02-16 01:05, Toke Høiland-Jørgensen wrote:
This switches the airtime scheduler in mac80211 to use a virtual
time-based
scheduler instead of the round-robin scheduler used before. This has
a
couple of advantages:

- No need to sync up the round-robin scheduler in firmware/hardware
with
  the round-robin airtime scheduler.

- If several stations are eligible for transmission we can schedule
both of
them; no need to hard-block the scheduling rotation until the head
of
the
  queue has used up its quantum.

- The check of whether a station is eligible for transmission becomes
  simpler (in ieee80211_txq_may_transmit()).

The drawback is that scheduling becomes slightly more expensive, as
we
need
to maintain an rbtree of TXQs sorted by virtual time. This means that
ieee80211_register_airtime() becomes O(logN) in the number of
currently
scheduled TXQs. However, hopefully this number rarely grows too big
(it's
only TXQs currently backlogged, not all associated stations), so it
shouldn't be too big of an issue.

@@ -1831,18 +1830,32 @@ void ieee80211_sta_register_airtime(struct
ieee80211_sta *pubsta, u8 tid,
 {
struct sta_info *sta = container_of(pubsta, struct sta_info, sta);
 	struct ieee80211_local *local = sta->sdata->local;
+	struct ieee80211_txq *txq = sta->sta.txq[tid];
 	u8 ac = ieee80211_ac_from_tid(tid);
-	u32 airtime = 0;
+	u64 airtime = 0, weight_sum;
+
+	if (!txq)
+		return;

 	if (sta->local->airtime_flags & AIRTIME_USE_TX)
 		airtime += tx_airtime;
 	if (sta->local->airtime_flags & AIRTIME_USE_RX)
 		airtime += rx_airtime;

+	/* Weights scale so the unit weight is 256 */
+	airtime <<= 8;
+
 	spin_lock_bh(&local->active_txq_lock[ac]);
+
 	sta->airtime[ac].tx_airtime += tx_airtime;
 	sta->airtime[ac].rx_airtime += rx_airtime;
-	sta->airtime[ac].deficit -= airtime;
+
+ weight_sum = local->airtime_weight_sum[ac] ?: sta->airtime_weight;
+
+	local->airtime_v_t[ac] += airtime / weight_sum;
Hi Toke,

Please ignore the previous two broken emails regarding this new
proposal
from me.

It looks like local->airtime_v_t acts like a Tx criteria. Only the
stations with less airtime than that are valid for Tx. That means
there
are situations, like 50 clients, that some of the stations can be used
to Tx when putting next_txq in the loop. Am I right?

I'm not sure what you mean here. Are you referring to the case where
new
stations appear with a very low (zero) airtime_v_t? That is handled
when
the station is enqueued.
Hi Toke,

Sorry for the confusion. I am not referring to the case that you
mentioned though it can be solved by your subtle design, max(local vt,
sta vt). :-)

Actually, my concern is situation about putting next_txq in the loop.
Let me explain a little more and see below.

@@ -3640,126 +3638,191 @@ EXPORT_SYMBOL(ieee80211_tx_dequeue);
 struct ieee80211_txq *ieee80211_next_txq(struct ieee80211_hw *hw, u8
ac)
 {
 	struct ieee80211_local *local = hw_to_local(hw);
+	struct rb_node *node = local->schedule_pos[ac];
 	struct txq_info *txqi = NULL;
+	bool first = false;

 	lockdep_assert_held(&local->active_txq_lock[ac]);

- begin:
-	txqi = list_first_entry_or_null(&local->active_txqs[ac],
-					struct txq_info,
-					schedule_order);
-	if (!txqi)
+	if (!node) {
+		node = rb_first_cached(&local->active_txqs[ac]);
+		first = true;
+	} else
+		node = rb_next(node);

Consider below piece of code from ath10k_mac_schedule_txq:

         ieee80211_txq_schedule_start(hw, ac);
         while ((txq = ieee80211_next_txq(hw, ac))) {
                 while (ath10k_mac_tx_can_push(hw, txq)) {
                         ret = ath10k_mac_tx_push_txq(hw, txq);
                         if (ret < 0)
                                 break;
                 }
                 ieee80211_return_txq(hw, txq);
                 ath10k_htt_tx_txq_update(hw, txq);
                 if (ret == -EBUSY)
                         break;
         }
         ieee80211_txq_schedule_end(hw, ac);

If my understanding is right, local->schedule_pos is used to record the
last scheduled node and used for traversal rbtree for valid txq. There
is chance that an empty txq is feeded to return_txq and got removed from
rbtree. The empty txq will always be the rb_first node. Then in the
following next_txq, local->schedule_pos becomes meaningless since its
rb_next will return NULL and the loop break. Only rb_first get dequeued
during this loop.

	if (!node || RB_EMPTY_NODE(node)) {
		node = rb_first_cached(&local->active_txqs[ac]);
		first = true;
	} else
		node = rb_next(node);

Ah, I see what you mean. Yes, that would indeed be a problem - nice
catch! :)

How about this? The nodes on the rbtree will be dequeued and removed
from rbtree one by one until HW is busy. Please note local vt and sta
vt will not be updated since txq lock is held during this time.

Insertion and removal from the rbtree are relatively expensive, so I'd
rather not do that for every txq. I think a better way to solve this
is to just defer the actual removal from the tree until
ieee80211_txq_schedule_end()... Will fix that when I submit this again.

Do you mean we keep the empty txqs in the rbtree until loop finishes and remove them in ieee80211_txq_schedule_end(may be put return_txq in it)? If it is the case, I suppose a list is needed to store the empty txqs so as to dequeue them in ieee80211_txq_schedule_end.

And one more thing,

+               if (sta->airtime[ac].v_t > local->airtime_v_t[ac]) {
+                       if (first)
+ local->airtime_v_t[ac] = sta->airtime[ac].v_t;
+                       else
+                               return NULL;

As local->airtime_v_t will not be updated during loop, we don't need to return NULL.


-Toke

--
Yibo



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