We only need 4 bytes of headroom for alignment purposes in the RX frame. It was previously higher for optimization purposes which are no longer possible due to DMA mappings. Signed-off-by: Ivo van Doorn <IvDoorn@xxxxxxxxx> --- diff --git a/drivers/net/wireless/rt2x00/rt2x00queue.c b/drivers/net/wireless/rt2x00/rt2x00queue.c index 8e86611..3ddce53 100644 --- a/drivers/net/wireless/rt2x00/rt2x00queue.c +++ b/drivers/net /wireless/rt2x00/rt2x00queue.c @@ -45,10 +45,11 @@ struct sk_buff *rt2x00queue_alloc_rxskb(struct rt2x00_dev *rt2x00dev, frame_size = entry->queue->data_size + entry->queue->desc_size; /* - * Reserve a few bytes extra headroom to allow drivers some moving - * space (e.g. for alignment), while keeping the skb aligned. + * The payload should be aligned to a 4-byte boundary, + * this means we need at least 3 bytes for moving the frame + * into the correct offset. */ - reserved_size = 8; + reserved_size = 4; /* * Allocate skbuffer. -- To unsubscribe from this list: send the line "unsubscribe linux-wireless" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
