From: Prasanna S. Panchamukhi <prasannax.s.panchamukhi at intel.com> This patch specifies the TX queue's minimum buffer room required to accommodate one smallest SDIO payload. Please refer the documentation in the code. Signed-off-by: Prasanna S. Panchamukhi <prasannax.s.panchamukhi at intel.com> --- drivers/net/wimax/i2400m/sdio.c | 7 +++++++ 1 files changed, 7 insertions(+), 0 deletions(-) diff --git a/drivers/net/wimax/i2400m/sdio.c b/drivers/net/wimax/i2400m/sdio.c index 7632f80..9bfc26e 100644 --- a/drivers/net/wimax/i2400m/sdio.c +++ b/drivers/net/wimax/i2400m/sdio.c @@ -483,6 +483,13 @@ int i2400ms_probe(struct sdio_func *func, sdio_set_drvdata(func, i2400ms); i2400m->bus_tx_block_size = I2400MS_BLK_SIZE; + /* + * Room required in the TX queue for SDIO message to accommodate + * a smallest payload while allocating header space is 224 bytes, + * which is the smallest message size(the block size 256 bytes) + * minus the smallest message header size(32 bytes). + */ + i2400m->bus_tx_room_min = I2400MS_BLK_SIZE - I2400M_PL_ALIGN * 2; i2400m->bus_pl_size_max = I2400MS_PL_SIZE_MAX; i2400m->bus_setup = i2400ms_bus_setup; i2400m->bus_dev_start = i2400ms_bus_dev_start; -- 1.6.6.1
