On Tue, 17 Dec 2024 11:54:32 +0800, Ma Ke <make_ruc2021@xxxxxxx> wrote:
> When device_add(&dev->dev) failed, calling put_device() to explicitly
> release dev->dev. Otherwise, it could cause double free problem.
Who frees it doublely?
If device_add() failed, the put_device is called inside device_add(),
why we need to call it again?
Maybe you need to say more?
Thanks.
>
> Found by code review.
>
> Cc: stable@xxxxxxxxxxxxxxx
> Fixes: 694a1116b405 ("virtio: Bind virtio device to device-tree node")
> Signed-off-by: Ma Ke <make_ruc2021@xxxxxxx>
> ---
> drivers/virtio/virtio.c | 1 +
> 1 file changed, 1 insertion(+)
>
> diff --git a/drivers/virtio/virtio.c b/drivers/virtio/virtio.c
> index b9095751e43b..ac721b5597e8 100644
> --- a/drivers/virtio/virtio.c
> +++ b/drivers/virtio/virtio.c
> @@ -503,6 +503,7 @@ int register_virtio_device(struct virtio_device *dev)
>
> out_of_node_put:
> of_node_put(dev->dev.of_node);
> + put_device(&dev->dev);
> out_ida_remove:
> ida_free(&virtio_index_ida, dev->index);
> out:
> --
> 2.25.1
>
