On Sat, Dec 05, 2020 at 10:15:11AM -0500, Alan Stern wrote: > On Sat, Dec 05, 2020 at 07:47:01PM +0700, Minh Bùi Quang wrote: > > Vào Th 6, 4 thg 12, 2020 vào lúc 23:12 Alan Stern > > <stern@xxxxxxxxxxxxxxxxxxx> đã viết: > > > Does this initialization end up using less memory than an explicit > > > memset() call? > > > > You mean speed? > > No, I mean memory space. > > A memset call requires a certain amount of instruction space (to push > the arguments and make the call) but no static data space. > Initialization requires some instruction space (to copy the data) and > static data space as well (to hold the data that is to be copied). > > Alan Stern > Thank you for your clarification, I didn't think about it before. As I check when compiling the code, with MAX_NUM_UDC=32 the initialization becomes xor eax,eax mov ecx,0x40 rep stos DWORD PTR es:[rdi],eax With MAX_NUM_UDC=2, the initialization becomes mov QWORD PTR [rbp-0x30],0x0 mov QWORD PTR [rbp-0x28],0x0 As I see, initialization does not require additional static data space. Am I right? Thanks, Quang Minh