On Tue, Oct 27, 2020 at 09:48:54AM +0000, Peter Chen wrote: > If you compile the code: > > unsigned int k = 0x80 << 24 + 0x81; > > It will report build warning: > warning: left shift count >= width of type [-Wshift-count-overflow] That's a separate issue. I believe (but haven't checked) that the << operator has lower precedence than +, so the compiler interprets the expression as: unsigned int k = 0x80 << (24 + 0x81); and it's pretty obvious why this causes an error. Instead, try compiling: unsigned int k = (0x80 << 24) + 0x81; You may get an error message about signed-integer overflow, but not about shift-count overflow. Alan Stern
