One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@xxxxxxxxxxxxxx> --- drivers/uwb/drp-ie.c | 5 ++--- 1 file changed, 2 insertions(+), 3 deletions(-) diff --git a/drivers/uwb/drp-ie.c b/drivers/uwb/drp-ie.c index 1d2a939cfcf8..ed993e363472 100644 --- a/drivers/uwb/drp-ie.c +++ b/drivers/uwb/drp-ie.c @@ -125,9 +125,8 @@ static struct uwb_ie_drp *uwb_drp_ie_alloc(void) { struct uwb_ie_drp *drp_ie; - drp_ie = kzalloc(sizeof(struct uwb_ie_drp) + - UWB_NUM_ZONES * sizeof(struct uwb_drp_alloc), - GFP_KERNEL); + drp_ie = kzalloc(struct_size(drp_ie, allocs, UWB_NUM_ZONES), + GFP_KERNEL); if (drp_ie) drp_ie->hdr.element_id = UWB_IE_DRP; return drp_ie; -- 2.20.1