Am Donnerstag, den 17.05.2018, 19:03 +0200 schrieb Guido Kiener: > +static int usbtmc488_ioctl_wait_srq(struct usbtmc_file_data *file_data, > + unsigned int __user *arg) > +{ > + struct usbtmc_device_data *data = file_data->data; > + struct device *dev = &data->intf->dev; > + int rv; > + unsigned int timeout; > + unsigned long expire; > + > + if (!data->iin_ep_present) { > + dev_dbg(dev, "no interrupt endpoint present\n"); > + return -EFAULT; > + } > + > + if (get_user(timeout, arg)) > + return -EFAULT; > + > + expire = msecs_to_jiffies(timeout); > + > + mutex_unlock(&data->io_mutex); There is such a thing as threads sharing file descriptors. That leads to the question what happens to the mutex if this ioctl() is called multiple times. Regards Oliver -- To unsubscribe from this list: send the line "unsubscribe linux-usb" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html