On Thu, 17 Aug 2023 13:29:26 -0600
Ross Zwisler <zwisler@xxxxxxxxxx> wrote:
> > + fail:
> > + /* Free the new values that were added */
> > + data_release(i, copy, types);
> > + /* Put back the old values */
> > + for (i--; i >= 0; i--) {
> > + copy_traceeval_data(types + i, NULL,
> > + copy + i, old + i);
>
> should be: old + i, copy + i);
>
> Right now we're copying 'copy' into 'old', but we want to be doing it the
> other way around so we restore 'copy' back to its saved state in 'old'
I need to change the parameter names to "src" and "dst" as I can't think of
"orig" and "copy" as which direction they go. I looked at that three times,
and still am confused. And probably reverse them too to make it equivalent
to memcpy():
>From memcpy() man page;
SYNOPSIS
#include <string.h>
void *memcpy(void *restrict dest, const void *restrict src, size_t n);
DESCRIPTION
The memcpy() function copies n bytes from memory area src to memory
area dest. The memory areas must not overlap. Use memmove(3) if
the memory areas do overlap.
As most standard libraries have it "dst, src" I'm pretty much thinking that
way, and my "direction" is always dst = src --> dst, src. And that's
exactly what I was thinking above :-p
-- Steve
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