On 22.04.19 г. 14:50 ч., Steven Rostedt wrote:
On Mon, 22 Apr 2019 14:29:49 +0300 "Yordan Karadzhov (VMware)" <y.karadz@xxxxxxxxx> wrote:I was hoping to test: string = cmdline_path() + "../../kernel-shark/lib/"; If that exists, then we know that we are in the source directory.I don't thing this is a good idea. If we search for plugins in a path that is defined like this: cmdline_path() + "/something/hard/coded/lib/"Your missing the "../.." part.Then the GUI will do one thing when started like this: ./kernelshark and anther thing when started like this: bin/kernelsharkNo it shouldn't, unless you moved the binary. I said to add "../../plugins" to the path that the kernelshark binary is executed from. If you were to move kernelshark, then yes. it would not longer give you the same result. If the binary is in: kernelshark/bin/kernelshark and you ran it as: kernelshark/bin/kernelshark using the path "kernelshark/bin" and adding "../lib" would give you "kernelshark/lib" directory. "kernelshark/bin/../lib" == "kernelshark/lib" Also, if you were to cd to kernelshark and run "bin/kernelshark" the path would be "bin/../lib" which would be equal to "lib" and being in the kernelshark directory, would give you the plugins directory that is the same as the previous command. If you cd to kernelshark/bin and ran "./kernelshark" we would then use "./../lib" which is the same as "../lib" which is still the same path as the other two. But last call we discussed a way to find the full path name of the binary being executed. And if that's the case, we could not only add "../lib" we could also check that the binary being executed is also in a "kernelshark/bin" first.
OK, now I think I understand what you want. Thanks! Yordan
and this can be very surprising behavior for the user The other solution has it own weaknesses, but at least it sounds like a simple rule: "If you want to use the compiled version of the plugins you have to start the GUI from the source code directory used to build. Otherwise the installed version of the plugins will be used."Building from source, then moving that source tree to another path shouldn't cause the binary to act differently. -- Steve
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