[tip:core/rcu] documentation: memory-barriers.txt: Correct example for reorderings

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Commit-ID:  8ab8b3e1837fc580b30263ed3c44dc34798714d9
Gitweb:     http://git.kernel.org/tip/8ab8b3e1837fc580b30263ed3c44dc34798714d9
Author:     Pranith Kumar <bobby.prani@xxxxxxxxx>
AuthorDate: Tue, 2 Sep 2014 23:34:29 -0400
Committer:  Paul E. McKenney <paulmck@xxxxxxxxxxxxxxxxxx>
CommitDate: Thu, 13 Nov 2014 10:34:55 -0800

documentation: memory-barriers.txt: Correct example for reorderings

Correct the example of memory orderings in memory-barriers.txt

Commit 615cc2c9cf95 "Documentation/memory-barriers.txt: fix important typo re
memory barriers" changed the assignment to x and y. Change the rest of the
example to match this change.

Reported-by: Ganesh Rapolu <ganesh.rapolu@xxxxxxxxxxx>
Signed-off-by: Pranith Kumar <bobby.prani@xxxxxxxxx>
Signed-off-by: Paul E. McKenney <paulmck@xxxxxxxxxxxxxxxxxx>
---
 Documentation/memory-barriers.txt | 22 +++++++++++-----------
 1 file changed, 11 insertions(+), 11 deletions(-)

diff --git a/Documentation/memory-barriers.txt b/Documentation/memory-barriers.txt
index 1073e01..f7fa635 100644
--- a/Documentation/memory-barriers.txt
+++ b/Documentation/memory-barriers.txt
@@ -121,22 +121,22 @@ For example, consider the following sequence of events:
 The set of accesses as seen by the memory system in the middle can be arranged
 in 24 different combinations:
 
-	STORE A=3,	STORE B=4,	x=LOAD A->3,	y=LOAD B->4
-	STORE A=3,	STORE B=4,	y=LOAD B->4,	x=LOAD A->3
-	STORE A=3,	x=LOAD A->3,	STORE B=4,	y=LOAD B->4
-	STORE A=3,	x=LOAD A->3,	y=LOAD B->2,	STORE B=4
-	STORE A=3,	y=LOAD B->2,	STORE B=4,	x=LOAD A->3
-	STORE A=3,	y=LOAD B->2,	x=LOAD A->3,	STORE B=4
-	STORE B=4,	STORE A=3,	x=LOAD A->3,	y=LOAD B->4
+	STORE A=3,	STORE B=4,	y=LOAD A->3,	x=LOAD B->4
+	STORE A=3,	STORE B=4,	x=LOAD B->4,	y=LOAD A->3
+	STORE A=3,	y=LOAD A->3,	STORE B=4,	x=LOAD B->4
+	STORE A=3,	y=LOAD A->3,	x=LOAD B->2,	STORE B=4
+	STORE A=3,	x=LOAD B->2,	STORE B=4,	y=LOAD A->3
+	STORE A=3,	x=LOAD B->2,	y=LOAD A->3,	STORE B=4
+	STORE B=4,	STORE A=3,	y=LOAD A->3,	x=LOAD B->4
 	STORE B=4, ...
 	...
 
 and can thus result in four different combinations of values:
 
-	x == 1, y == 2
-	x == 1, y == 4
-	x == 3, y == 2
-	x == 3, y == 4
+	x == 2, y == 1
+	x == 2, y == 3
+	x == 4, y == 1
+	x == 4, y == 3
 
 
 Furthermore, the stores committed by a CPU to the memory system may not be
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