-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi all, I've been wondering this for a while, and figured I'd ask here. How does one determine the amount of free RAM on a gnu/linux system? If I run "free -m" on one of my machines right after boot, I get something like: total used free shared buffers cached Mem: 2957 2933 24 0 78 1590 - -/+ buffers/cache: 1263 1694 Swap: 925 0 925 Here's what I'm getting at. First, I know what runs on this box, and this machine starts up with a limited amount of programs running, and pretty much stays like that as long as it remains powered up (running ps confirms this). What this machine starts with should take up about 1480 megs of RAM according to my calculations. Ok, let's add 100 megs extra for the system itself, and to make sure I've really accounted for what runs on this box. That would come out to about 1580 megs of RAM used, let's round up to 1600. I have also confirmed that if I physically pull a gig of RAM out, the machine will still run everything without heavy use of swap. Second, if the machine stays up for 24 hours or longer, the amount of free RAM doesn't change much, but a few megs of swap is used. I assume this is for processes which haven't been used in a while. So, why am I seeing something around 20 megs free, instead of something around a gig? To put it another way, if I wanted to run this machine with a minimum amount of RAM how would I figure out how much I really need? Thanks in advance. Greg - -- web site: http://www.romuald.net.eu.org gpg public key: http://www.romuald.net.eu.org/pubkey.asc skype: gregn1 (authorization required, add me to your contacts list first) - -- Free domains: http://www.eu.org/ or mail dns-manager at EU.org -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.10 (GNU/Linux) iEYEARECAAYFAk+hrW4ACgkQ7s9z/XlyUyDZzACgwce9sLkd/+Pw8rvfzNrNRBIF KcwAnjSjN5WHVfmr/HWV1/Jfu+5zeQGY =+PFb -----END PGP SIGNATURE-----
