-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi again all. I've just been looking at a converted pdf of my motherboard manual. While it doesn't specifically tell you in what order you should place your memory modules, it does say that the installed memory array has to be 68 or 72 bits wide. How do I compute that? My guess is that I'd need to know how many bits there are per module, but I don't know what the answer to that is. Thanks. Greg On Tue, Mar 23, 2004 at 12:14:27PM -0600, Gregory Nowak wrote: > I've just tried the mem=512M option, and here's what I get. > > user-defined physical RAM map: > user: 0000000000000000 - 00000000000a0000 (usable) > user: 00000000000f0000 - 0000000000100000 (reserved) > user: 0000000000100000 - 0000000017ff0000 (usable) > user: 0000000017ff0000 - 0000000017ff3000 (ACPI NVS) > user: 0000000017ff3000 - 0000000018000000 (ACPI data) > user: 00000000ffff0000 - 0000000100000000 (reserved) > 383MB LOWMEM available. > > Greg > > - -- Free domains: http://www.eu.org/ or mail dns-manager at EU.org -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.2.3 (GNU/Linux) iD8DBQFAYK+I7s9z/XlyUyARAujvAJ9KfM4lVp7edP5tRHLX+oiB2n+ePQCaA/PJ OZzpK092cSMHDBdOa7mftIc= =cV1J -----END PGP SIGNATURE-----
