When linearizing a call expression, the corresponding instruction is
allocated very early:
- before the valdity are done
- before the linearization is handled to one of the specific methods
In both case it means that the allocated instruction is not used.
Fix this by doing the allocation only once it's needed.
Signed-off-by: Luc Van Oostenryck <luc.vanoostenryck@xxxxxxxxx>
---
linearize.c | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/linearize.c b/linearize.c
index 7248fa56b2ef..cf87545c7a18 100644
--- a/linearize.c
+++ b/linearize.c
@@ -1533,7 +1533,7 @@ static pseudo_t linearize_assignment(struct entrypoint *ep, struct expression *e
static pseudo_t linearize_call_expression(struct entrypoint *ep, struct expression *expr)
{
struct expression *arg, *fn;
- struct instruction *insn = alloc_typed_instruction(OP_CALL, expr->ctype);
+ struct instruction *insn;
pseudo_t retval, call;
struct ctype *ctype = NULL;
struct symbol *fntype;
@@ -1554,6 +1554,7 @@ static pseudo_t linearize_call_expression(struct entrypoint *ep, struct expressi
ctype = &fntype->ctype;
+ insn = alloc_typed_instruction(OP_CALL, expr->ctype);
add_symbol(&insn->fntypes, fntype);
FOR_EACH_PTR(expr->args, arg) {
pseudo_t new = linearize_expression(ep, arg);
--
2.31.1
