The addresses needed by memory output operands are linearized
(and placed) after the ASM instruction needing them.
So, add a test case for this.
Signed-off-by: Luc Van Oostenryck <luc.vanoostenryck@xxxxxxxxx>
---
validation/linear/asm-out0.c | 26 ++++++++++++++++++++++++++
1 file changed, 26 insertions(+)
create mode 100644 validation/linear/asm-out0.c
diff --git a/validation/linear/asm-out0.c b/validation/linear/asm-out0.c
new file mode 100644
index 000000000000..64d154ed5ad7
--- /dev/null
+++ b/validation/linear/asm-out0.c
@@ -0,0 +1,26 @@
+static void asm_out0(void)
+{
+ int mem;
+ asm volatile ("[%1] <= 0" : "=m" (mem));
+}
+
+/*
+ * check-name: asm-out0
+ * check-command: test-linearize -fdump-ir $file
+ * check-known-to-fail
+ *
+ * check-output-start
+asm_out0:
+.L0:
+ <entry-point>
+ symaddr.64 %r1 <- mem
+ asm "[%1] <= 0"
+ out: "=m" (%r1)
+ br .L1
+
+.L1:
+ ret
+
+
+ * check-output-end
+ */
--
2.30.0
