On Sun, Aug 20, 2017 at 8:31 AM, Dibyendu Majumdar
<mobile@xxxxxxxxxxxxxxx> wrote:
> Hi,
>
> I am looking at the parse tree for following snippet:
>
> void main(int argc, const char *argv[])
> {
> 5;
> 6.5;
> "hello";
> }
>
> I see that 5 is treated as EXPR_VALUE, 6.5 as EXPR_FVALUE, but "hello"
> is treated as EXPR_SYMBOL. Why is that?
Because "hello" is array of char from type point of view.
It is same as
char no_ident [] = {'h', 'e', 'l', 'l', 'o', '\0'};
except it does not have the name(sym->ident) for this symbol.
Chris
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