Small improvement to output from show_instruction()

[Dibyendu Majumdar <mobile@xxxxxxxxxxxxxxx>]

Hi

To aid understanding and for debugging it is useful if the instruction
type is indicated when the type is not an integer value. I suggest
following small change to show_instruction():

 if (opcode < ARRAY_SIZE(opcodes)) {
  const char *op = opcodes[opcode];
  if (!op)
   buf += sprintf(buf, "opcode:%d", opcode);
  else
   buf += sprintf(buf, "%s", op);
  if (insn->type && is_float_type(insn->type))
   buf += sprintf(buf, ".f%d", insn->size);
  else if (insn->size)
   buf += sprintf(buf, ".%d", insn->size);
  if (insn->type) {
   if (is_ptr_type(insn->type))
    buf += sprintf(buf, "*");
  }
  memset(buf, ' ', 20);
  buf++;
 }

For example, the output for following:

extern int printf(const char *, ...);
int main(void)
{
    printf("%f\n", (double)-1);
    return 0;
}

is shown as:

main:
.L0:
        <entry-point>
        symaddr.64* %r1 <- <anon symbol:0000024A51894818>
        push.64*    %r1
        push.f64    $-1
        call.32     %r2 <- printf
        ret.32      $0


Thanks and Regards
Dibyendu
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