On Fri, Nov 18, 2011 at 9:41 AM, Pekka Enberg <penberg@xxxxxxxxxx> wrote:
>> I'm implementing support for function pointer calls and I noticed that
>> ->func->sym in 'strut instruction' is not SYM_NODE for function
>> pointers like it is for normal functions. Why is that?
On Fri, Nov 18, 2011 at 2:24 PM, Linus Torvalds
<torvalds@xxxxxxxxxxxxxxxxxxxx> wrote:
> There *is* no real symbol to work with. It's an expression. The
> expression may not even be a symbol, it could easily be some real
> expression like
>
> ret = (flag ? fn1 : fn2)(arg1, arg2);
>
> so trying to make up some "symbol" for it is just lying and crazy.
Aah, the current code by Jeff for OP_CALL makes perfect sense now. Thanks!
Pekka
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