On Mon, Jun 3, 2019 at 9:43 PM David Laight <David.Laight@xxxxxxxxxx> wrote:
>
> From: Masahiro Yamada
> > Sent: 03 June 2019 12:45
> > On Mon, Jun 3, 2019 at 8:16 PM David Laight <David.Laight@xxxxxxxxxx> wrote:
> > >
> > > From: Masahiro Yamada
> > > > Sent: 03 June 2019 11:49
> > > >
> > > > To print the pathname that will be used by shell in the current
> > > > environment, 'command -v' is a standardized way. [1]
> > > >
> > > > 'which' is also often used in scripting, but it is not portable.
> > >
> > > All uses of 'which' should be expunged.
> > > It is a bourne shell script that is trying to emulate a csh builtin.
> > > It is doomed to fail in corner cases.
> > > ISTR it has serious problems with shell functions and aliases.
> >
> > OK, I do not have time to check it treewide.
> > I expect somebody will contribute to it.
> >
> >
> >
> > BTW, I see yet another way to get the command path.
> >
> > 'type -path' is bash-specific.
>
> 'type' itself should be supported by all shells, but the output
> format (esp for errors) probably varies.
>
> > Maybe, we should do this too:
> >
> > diff --git a/scripts/mkuboot.sh b/scripts/mkuboot.sh
> > index 4b1fe09e9042..77829ee4268e 100755
> > --- a/scripts/mkuboot.sh
> > +++ b/scripts/mkuboot.sh
> > @@ -1,14 +1,14 @@
> > -#!/bin/bash
> > +#!/bin/sh
>
> /bin/sh might be 'dash' - which is just plain broken in so many ways.
> Try (IIRC) ${foo%${foo#bar}}
> It might even be the original SYSV /bin/sh which doesn't support $((expr))
> or ${foo#bar} - but that may break too much, but $SHELL might fix it.
We cannot use any tool
if you start to argue like
"Hey, I know ancient implementation that did not work as expected".
Nobody can cover all corner-cases.
That's why we have standard.
I think the reliable source is the
Open Group Specification.
The behavior of /bin/sh is defined here:
http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_01
${parameter%[word]} and ${parameter#[word]} are defined,
so we can use them in /bin/sh scripts.
> dash probably has the rather obscure bug in stripping '\n' from $(...)
> output that I found and fixed in NetBSD's ash may years ago.
> Try: foo="$(jot -b "" 130)"
> All 130 '\n' should be deleted.
> Mostly it fails to delete all the '\n', but it can remove extra ones!
>
> David
>
> -
> Registered Address Lakeside, Bramley Road, Mount Farm, Milton Keynes, MK1 1PT, UK
> Registration No: 1397386 (Wales)
--
Best Regards
Masahiro Yamada
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